The Forum > Math & Science > Integration of Distance

While pondering the value of integrals and derivatives, I stumbled on to a question. What are you left with if you take the integral of distance? In case I'm wording this wrong (it's been awhile since math, and I feel rusty) when I say distance I refer to what you get when you take the integral of velocity, given that you know C. |

In Dimensional Analysis (using L for Length and T for Time): Acceleration is represented by L ^{1}T^{-2}Velocity is represented by L ^{1}T^{-1}Distance is represented by L ^{1}T^{0}So integrating Distance would produce something represented by L ^{1}T^{1}As far as I know there are no real measurements that use this representation (or a similar Dimension, which could easily be changed) The closest I could find to "ms" (Metre-Second) Would be a Coulomb-Metre per Amp, which breaks down to this, but would be completely fictitious: (Including A for Amperage) Coulomb = A ^{1}L^{0}T^{1}Metre = A ^{0}L^{1}T^{0}Coulomb-Metre = A ^{1}L^{1}T^{1}Amp = A ^{1}L^{0}T^{0}Coulomb-Metre per Amp = A ^{0}L^{1}T^{1}I have no idea how this measurement would be implemented in reality |

The Forum > Math & Science > Integration of Distance